x^2+29x-492=0

Solution for x^2+29x-492=0 equation:

Simplifying
x2 + 29x + -492 = 0

Reorder the terms:
-492 + 29x + x2 = 0

Solving
-492 + 29x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-41 + -1x)(12 + -1x) = 0

Subproblem 1
Set the factor '(-41 + -1x)' equal to zero and attempt to solve:

Simplifying
-41 + -1x = 0

Solving
-41 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '41' to each side of the equation.
-41 + 41 + -1x = 0 + 41

Combine like terms: -41 + 41 = 0
0 + -1x = 0 + 41
-1x = 0 + 41

Combine like terms: 0 + 41 = 41
-1x = 41

Divide each side by '-1'.
x = -41

Simplifying
x = -41
Subproblem 2
Set the factor '(12 + -1x)' equal to zero and attempt to solve:

Simplifying
12 + -1x = 0

Solving
12 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1x = 0 + -12
-1x = 0 + -12

Combine like terms: 0 + -12 = -12
-1x = -12

Divide each side by '-1'.
x = 12

Simplifying
x = 12
Solution
x = {-41, 12}